Where Quality Counts
and Show Dogs Hunt

Where Quality Counts and Show Dogs HuntWhere Quality Counts and Show Dogs HuntWhere Quality Counts and Show Dogs Hunt

520-227-1845

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    • Home
    • About Evermore Pointers
    • Current Pointers
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520-227-1845

Where Quality Counts
and Show Dogs Hunt

Where Quality Counts and Show Dogs HuntWhere Quality Counts and Show Dogs HuntWhere Quality Counts and Show Dogs Hunt
  • Home
  • About Evermore Pointers
  • Current Pointers
  • Litter Page
  • Evermore Pups
  • Pointers of Note
  • Sires of Evermore Pups
  • Coat Colors & Genetics
  • Standards & Education
  • LeashUP!

Pointer Phenotype Chart

This chart will give the CHANCES in PERCENTAGES of each color that CAN  POSSIBLY occur from a particular mating (excluding tri-colors and  solids).

Pointer Genotypes:
Black 1      BBEE carry no recessive type
Black 2      BbEE carry liver
Black 3      BBEe carry orange
Black 4      BbEe carry liver, orange and lemon
Liver 5       bbEE carry no recessive type
Liver 6       bbEe carry lemon
Orange 7  BBee carry no recessive type
Orange 8  Bbee carry lemon
Lemon 9   bbee carry no recessive type 

Punnett Squares

Let's say you want to find the possible genotypes (the "genetic code") for a planned Pointer litter.
-The sire's phenotype is black (the actual coloration of the dog) and you know that his genotype is a Black 3, black carry orange (BBEe).  

-The dam's phenotype is liver and you know that her genotype is a Liver  6, liver carry lemon (bbEe).

Here's an easy way to set up the Punnett Square to find the off springs' possible genotypes.

-First take the "B" part of each of the dogs' genotype.  

-Put the stud dog's "B's" (BB) along the top of the graph.

-The dam's "B's" (bb) along the side.

This is how the square will look set up.


Then you take a "B" from the sire and match it with a "B" from the dam to fill in the graph. 


Now do the same with the "E's".  

The sire and the dam are both Ee. 

Now you need to find all possible combinations between the two.   

From the "B" square, we see that the only outcome is Bb.  

From the "E" square  we have several combinations; EE, Ee and ee.  

So the combinations would present as follows;   BbEE, BbEe and Bbee.  

Then find the combinations on the Genotype chart to see what could be expected.

Pointer Genotypes

Black 1      BBEE carry no recessive type
Black 2      BbEE carry liver
Black 3      BBEe carry orange
Black 4      BbEe carry liver, orange and lemon
Liver 5       bbEE carry no recessive type
Liver 6       bbEe carry lemon
Orange 7  BBee carry no recessive type
Orange 8  Bbee carry lemon
Lemon 9   bbee carry no recessive type 

So we see that the possible genotypes would be Black 2, Black 4 and Orange 8.

Therefore, according to the phenotype chart the possible outcome would be 75% black and 25% orange colorations produced.

Links to genetic testing labs

UC Davis LabsVetGenEmbark

Pointer Coat Colors

Black and White

    Evermore Pointers

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